"strength" statistic

[eewilliams]

How is the "strength" statistic calculated? What does it mean?

[dominationnation]

use the other search button and find one of the other 10000000 threads about this

[eewilliams]

What other search button?

[dominationnation]

sorry didnt mean to write "other"

but did you do it?

did you find out what it means

[eewilliams]

Yes, I did it, but got so many hits I couldn't find an answer. You were right about the1000000 threads! lol. Do you have a quick answer before I go back and refine my search?

[dominationnation]

The original Conquer Club script by Tr0y calculates it as follows:

s = a + p - (2/3 * c)

where
s is strength
a is the number of armies currently held by a player
p is the potential armies gained for next turn
c is the number of countries currently held by a player
the - (2/3 * c) expression represents the notion of dispersion of your forces. In other words, it is generally better (i.e., of higher strength) to have more armies on fewer countries than to have fewer armies on more countries.

potential armies is the sum of armies due for holding a number of countries (at least three, with an additional army added for each multiple of 3 over 11 countries held) and any continent bonuses due.

The Conquer Club - Roberts Mods (by stocksr) calculates it as follows (this is the answer to the question you asked):

s = a + e - (2/3 * c)

where
e is the number of expected armies gained for next turn.

It includes the potential armies described above and additionally factors in an estimate of the number of armies due in the next turn because of cashing in a card set.

The calculation for the size of the card bonus is calculated as follows:

(probability of having a card set to cash) * (value of cashing a card set).

For the case of an escalating card game the probability of having a card set to cash is calculated as follows:

p(0 - 2) = 0
p(3) = .3341
p(4) = .778
p(5) = 1

where p(n) is the probability of having a card set to cash when the player holds n cards.

The value of cashing a card set is known in an escalating game.

For the case of a flat rate card game the same probabilities of having a card set as the escalating case are used.

The value of cashing a card set is estimated at 7 (which is approximately (4 + 6 + 10) / 3) since the value of the set cannot be determined without knowing the color composition of the set cashed.

In this thread I make a proposal for calculating the armies due next turn (in a flat rate game) using slightly different probabilities and taking into consideration the 2 army per country bonus one gets for owning the country specified on the card cashed:

http://www.conquerclub.com/forum/viewtopic.php?t=15620



thanks thaitia spelling?

[mibi]

its a pointless metric, best to avoid it and use your own judgment.

[Robinette]

its a pointless metric, best to avoid it and use your own judgment.

Perhaps if it were 2 numbers... The minimum and the maximum possible...

Then you use your judgement as to if the opponent has a set or not, but at least the #'s are accurate "one way or the other"

[detlef]

its a pointless metric, best to avoid it and use your own judgment.

Good stuff here.

[oVo]

The white dice negate the accurate calculation of strength with the randomness of their odds.
I've lost absurd numbers of armies against nearly unfortified territories.

So you always have to figure in the L factor, where L = luck.

[GreecePwns]

So you always have to figure in the L factor, where L = luck.

Man we have a mathematician here.

Here is a math formula for you: C+7=W where C is my current post #, and 7=7 and W=wanted post # (500)

[oVo]

There might also be an H factor to be considered in direct proportion to strength.

It could have an effect your attitude after an attack, where H = humor

or

directly influence the duration of an attack, where H = hemorrhoid.