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Tie Breaker:
dean of 7 v ooge: 2-8 dean of 7 : 10 or 18
dean of 7 v lordlau1: 8-4
dean of 7 v Wizz00: 8-6 lordlau1 : 11 or 19
ooge v lordlau1: 8-7 ooge : 16 or 21
ooge v Wizz 00: 5-8
lordlau1 v Wizz00: 8-5 Wizz00 : 19
No matter who wins the match between Wizz00 and Ratrin, dean of 7 will be eliminated.
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Wizz00 & sandman175 move to the Finals
Finals: 18 games issued so far.
Wizz00 - 7
Sandman175 - 10
Winner: Sandman175
Combined Scores:
Division A:
Ratrin 17 +6 = 23
sandman175 17 + 7 = 24
lordlau1 11 + 8 = 19
harvmax 10 + 8 = 18
Evil Semp 11 + 5 = 16
Marshallbobby 11+5 = 14
rmjw10 6 + 3 = 10
Division B:
deanof7 14 + 10 = 24
jpk 14 + 6 = 20
Wizz00 13 + 5 = 18
ooge 8 + 9 = 17
mickunited333 6 + 9 = 15
adam666 8 + 3 = 11
In case of a tie, The tiebreakers will be as follows:
1. I will take the totals of the head-to-head competitions amongst those tied. Four instance if there are three people tied. Player A beat player B in seven games and And beat player C in four games. Then player A will have a total of 11.
2. If there are still people tied at the end of step one, Then I will take the total number Of turns that it took each person Winning their games. For example, player A, Took eight turns to win in his first game and seven turns to win in his second game and 11 terms to win in his third game, Then he will have a score of 25. And so on for the other players that are tied. This will only be the games that they played head-to-head.
3. If there is still a tie I will now go back to step one. And if it's still tied I will throw the names into random.org. Hopefully I have eliminated some in the first two steps.