Moderator: Community Team
and defense too much advantage in beginning making it hard to start outSir. Ricco wrote:Hmm… very interesting.I don’t know though. I think it would give the attack a little too much advantage.
I am not sure if this is true. Lets say that the game was set to 5 attack dice, 3 defense dice. In the first round you could add your 3 reinforcements on one country (as most do now anyway) giving you a 5 attack - 3 defense which in my opinion sounds more logical than the current 3 -2 where you very often simply strike out completely (the ever dreaded first turn double loss, no card result, game sucks from there on outHerakilla wrote:and defense too much advantage in beginning making it hard to start outSir. Ricco wrote:Hmm… very interesting.I don’t know though. I think it would give the attack a little too much advantage.
nice thought, but how you say it, has not much to do with the number of dices...Herakilla wrote:the extra dice that attackers get really only gives the advantage in the long term, if you lose even one of those 5 your attacking with your already down an out a die. thats why when the numbers get higher on both sides the attacker gains more and more of an advantage
Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:Herakilla wrote:one other thing, defenders would gain more of an advantage than attackers, each die you add adds another 1/6 chance to get a 6 which is an auto win for defenders with 3 you have a 3/6 of getting one 6 so effectively every other roll should have a 6 instead of every 6th 3rd roll and that can be painful
basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote: Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
With 5 dice, odds are about 1/6 that you get 2 sixes.Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how to
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD
Herakilla isn't the sharpest tool in the shed.Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote: Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD
if you arent a junior yet then try to remember 4th grade math when your a junior! especially when you got calculus and ap calculusRisktaker17 wrote:Herakilla isn't the sharpest tool in the shed.Herakilla wrote:basically with 2 dice you have a 1/36 chance of getting 2 6's but i cant remember how toPhiller wrote: Dont think that is right. Just with the current rules you eliminate dices against each other. Example of 5-3 dice setup as discuseed above:
Attacker Dice: 6 - 6 - 3 - 2 - 1
Defender Dice: 6 - 5 - 2
Result 1st Pair: 6 - 6 (defender wins)
Result 2nd Pair: 6 - 5 (attacker wins)
Result 3rd Pair: 3 - 2 (attacker wins)
End Result: Defender loses 2, Attacker loses 1.
the chances of you getting TWO 6's in a roll are low, even if you get 5 dice
i'd do the math but its like 4th grade math and i cant remember it XD![]()
![]()
I kid Hera, we are friends
